 (17)Write a program to enter any number and check it is armstrong No or not in Cpp

vProgram

#include<iostream.h> #include<conio.h> class armstrong {   int n,no,r,c;   public:     palindrom()     { r=0;     }     void getdata()     {      cout<<"\n\t\t Enter Number:";     cin>>no;     }     void putdata()     {        c=no;       for( ;no>=1; )       {        n=no%10;        r=r+(n*n*n);        no=no/10;       }       if(c==r)       {       cout<<"\n\t\t A Number Is Armstrong !!";       }       else       {        cout<<"\n\t\t A Number Not Armstrong !!";       }      }   };   void main()   {    clrscr();    armstrong p1;    p1.getdata();    p1.putdata();    getch();  }

vOutput:

Enter Number:153 A Number Is Armstrong !!

(16)write a program to enter any no and check it is prime No Or Not. in Cpp(Using Class)

vProgram

#include<iostream.h> #include<conio.h> class primeno {   int n,no,c;   public:     primeno()     { c=0;     n=1;     }     void input()     {      cout<<"\n\t\t Enter Number:";     cin>>no;     }     void output()     {       while(n<=no)       {        if(no%n==0)        {          c++;        }        n++;       }       if(c==2)       {       cout<<"\n\t\t A Prime  Number ";       }       else       {        cout<<"\n\t\t A  Not Prime number!!";       }      }   };   void main()   {    clrscr();    primeno p1;    p1.input();    p1.output();    getch();  }

vOutput

Enter Number:151  A prime Number

(15)Write a Program to enter any no and check it is palidrom no or Not.in Cpp(using Class)

vProgram

#include<iostream.h> #include<conio.h> class palindrom {   int n,no,r,c;   public:     palindrom()     { r=0;     }     void getdata()     {      cout<<"\n\t\t Enter Number:";     cin>>no;     }     void putdata()     {        c=no;       while(no>=1)       {        n=no%10;        r=(r*10)+n;        no=no/10;       }       if(c==r)       {       cout<<"\n\t\t A Palindrom Number Is:"<<r;       }       else       {        cout<<"\n\t\t A Number Not Palindrom !!";       }      }   };   void main()   {    clrscr();    palindrom r1;    r1.getdata();    r1.putdata();    getch();  }

vOutput

Enter Number:343 A Palindrom number Is:343

(14)Write a program to enter any No. and display reverse No. in CPP (Using Class)

vProgram

#include<iostream.h> #include<conio.h> class reverse {   int n,no,r;   public:     reverse()     { r=0;     }     void getdata()     {      cout<<"\n\t\t Enter Number:";     cin>>no;     }     void putdata()     {       while(no>=1)       {        n=no%10;        r=(r*10)+n;        no=no/10;       }       cout<<"\n\t\t A reverse Number Is:"<<r;      }   };   void main()   {    clrscr();    reverse r1;    r1.getdata();    r1.putdata();    getch();  }

vOutput

Enter Number:123 A reverse Number Is:321

(13)Write a Program to enter electronics util and total bill use following condition in Cpp

Unit        Rate        Perunit

100         0              50-0

200         1              150-50

300         2              250-200

400         3              350-450

500         4              450-800

>500       5              550-1250

vProgram

#include<iostream.h> #include<conio.h> void main() {   int unit,tot;   clrscr();   cout<<"\n\t\t Enter Unit:";   cin>>unit;   if(unit>500)   {     tot=(unit-500)*5+1000;    }    else if(unit>400)    {      tot=(unit-400)*4+600;    }    else if(unit>300)    {      tot=(unit-300)*3+300;    }    else if(unit>200)    {     tot=(unit-200)*2+100;    }    else if(unit>100)    {      tot=(unit-100)*1;    }    else    {      tot=0;    }    cout<<"\n\t\t Your Total Bill Is:"<<tot;    getch();    }

vOutput

Enter Unit:200 Your Total bill Is:100

(12) Write a Program to enter any number and check (i)it is divisible by 3 only (ii) it is divisible by 5 only (iii) it is divisible by 3 & 5 both in Cpp

vProgram

/*WAP divisible by 3 and 5 or both */ #include<iostream.h> #include<conio.h> void main() {  int no;  clrscr();  cout<<"\n\t\t Enter Number :";  cin>>no;  if(no%3==0)  {   if(no%5==0)   {     cout<<"divisible by 3 & 5";     }     else     {     cout<<"divisible by 3 Only";     }    }    else    {       if(no%5==0)       {        cout<<"\n\t\t Divisible By 5 Only";       }       else       {        cout<<"\n \t\tnot Divisible 5 & 3";        }     }     getch();   }

vOutput

Enter number:30 Divisible by 3 & 5

(11)Write a program Enter Year Find It Leep YEAR Or Not. in C++

vProgram

#include<iostream.h> #include<conio.h> void main() {  int year;  cout<<"Enter Check Year:";  cin>>year;  if(year%400==0)  {  cout<<year<<"\tLeap Year:";  }  else if(year%100==0)  { cout<<year<<"\t NOT Leap Year:";  }  else if(year%4==0)  {   cout<<year<<"\tLeap Year:";  }  else  {   cout<<year<<"\tNOT Leap Year:";  }  getch();  }

vOutput:

Enter Check Year:2016 2016  leap Year

(10)WAP Enter Salary And Bonuse Rate And Find Out Total Salary in cpp

vProgram

#include<iostream.h> #include<conio.h> void main() {   float salary,tot,bns;   clrscr();   cout<<"\n\t\tEnter Employee Salary:";   cin>>salary;   cout<<"\n\t\t Enter Bonuse Rate:";   cin>>bns;   tot=salary+(salary*bns/100); //Salary Plus Bonuse Formula   cout<<"\n\t\t A Employee Total Salary Is:"<<tot;   getch();   }

vOutPut:

Enter Employee Salary:5000 Enter Bonuse Rate:5 A Employee Total Salary Is:5250

(9) WAP Simple Interest Find Out in cpp

vProgram.

#include<iostream.h> #include<conio.h> void main() {   int amount,rate,time,ans;   clrscr();   cout<<"\n\t\tEnter Amount:";   cin>>amount;   cout<<"\n\t\tEnter Rate:";   cin>>rate;   cout<<"\n\t\tEnter Time/year:";   cin>>time;   ans=(amount*rate*time)/100;//simple Interest Formula   cout<<"\n\t\t A Simple Interest Is:"<<ans;   getch();   }

vOutput:

Enter Amout:1000 Enter Rate:10 Enter Time/Year:1 A Simple Interest Is:100